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5x^2+25.25x-176=0
a = 5; b = 25.25; c = -176;
Δ = b2-4ac
Δ = 25.252-4·5·(-176)
Δ = 4157.5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25.25)-\sqrt{4157.5625}}{2*5}=\frac{-25.25-\sqrt{4157.5625}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25.25)+\sqrt{4157.5625}}{2*5}=\frac{-25.25+\sqrt{4157.5625}}{10} $
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